Expand: $(2 x + 3 y) (2 x - 3 y)$

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Solution

The given expression $(2 x + 3 y) (2 x - 3 y)$ can be expanded as shown below:

$(2 x + 3 y) (2 x - 3 y) = [(2 x \times 2 x) + (2 x \times - 3 y) + (3 y \times 2 x) + (3 y \times - 3 y)] = {4 x}^{2} - 6 x y + 6 x y - 9 y^{2} = {4 x}^{2} - 9 y^{2}$

Hence $(2 x + 3 y) (2 x - 3 y) = 4 x^{2} - 9 y^{2}$

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Similar questions

Simplify: $(2 x - 3 y) (2 x + 3 y)$

(2 x + 3 y)^{2}

(2 x - 3 y)^{2}

(2 x + 3 y) (2 x - 3 y)

(2 x - 3 y) (2 x + 3 y) = (2 x)^{2} - (3 y)^{2}

$(2 x - 3 y)^{3} + (x + 3 y)^{3} + 3 (2 x - 3 y)^{2} (x + 3 y) + 3 (2 x - 3 y) (x + 3 y)^{2} =$

2 x^{2} - 18 y^{2}

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