wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Expand (2x3y)3

Open in App
Solution

(2x3y)3=(2x)33(2x)2(3y)+3(2x)(3y)2(3y)3
=8x336x2y+54xy227y3

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Algebraic Identities
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon