Question

Expand ${(3\times 7)}^5$ and write in exponent form.

Answer 1

As we know for any non-zero integers $\text{'}a\text{'}$ and $\text{'}b\text{'}$ and for any natural number $\text{'}n\text{'}$, $a^n\times b^n={\left(a\times b\right)}^n$.

So, ${(3\times 7)}^5$ is in the form of ${(a\times b)}^n$ only, thus, we can write exponent individually on each base, i.e., ${(3\times 7)}^5$$=3^5\times 7^5$.

Hence, ${(3\times 7)}^5$$=3^5\times 7^5$ in the expanded form.