(3a b + 4c)^2 = (3a + ( b) + 4c)^2 nbsp;Using, nbsp; (a+b+c)^2 = a^2+b^2+c^2+2ab+2bc+2ac = (3a)^2 + ( b)^2 + (4c)^2 + 2 (3a) ( b) + 2( b) (4c ...

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Multiplication of Any Polynomial

Expand 3a -...

Question

Expand $(3 a - b + 4 c)^{2}$

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Solution

$(3 a - b + 4 c)^{2} = (3 a + (- b) + 4 c)^{2}$
Using, $(a + b + c)^{2} = a^{2} + b^{2} + c^{2} + 2 a b + 2 b c + 2 a c$
$= (3 a)^{2} + (- b)^{2} + (4 c)^{2} + 2 (3 a) (- b) + 2 (- b) (4 c) + 2 (4 c) (3 a)$
$= 9 a^{2} + b^{2} + 16 c^{2} - 6 a b - 8 b c + 24 c a$

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