Expand: (3x−2b+5c)2
Using identity (a−b+c)2=a2+b2+c2−2ab−2bc+2ac
= (3x)2+(2b)2+(5c)2−2(3x)(2b)−2(2b)(5c)+2(3x)(5c)
= 9x2+4b2+252−12xb−20bc+30xc
Expand (i) (2a−5b−7c)2 (ii) (−3a+4b−5c)2 (iii) (12a−14b+2)2
Expand (4a–2b–3c)2