Expand $6 (p - q)^{2} - (p - q) - 15$

p^{2} + q^{2} - 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 p^{2} - 12 p q + 6 q^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 p^{2} - 12 p q + 6 q^{2} - p + q - 15

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6 p^{2} - 12 p q + 6 q^{2} + p - q - 15

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $6 p^{2} - 12 p q + 6 q^{2} - p + q - 15$

$6 (p - q)^{2} - (p - q) - 15 = 6 (p^{2} - 2 p q + q^{2}) - (p - q) - 15 = 6 p^{2} - 12 p q + 6 q^{2} - p + q - 15$

Suggest Corrections

Similar questions

12 p^{2} - 7 p = - 1

6 q^{2} - 7 q + 2 = 0

26 p^{2} q^{2}

12 p q

p^{2} - 8 p + 15 = 0

q^{2} - 5 q = - 6

p + q = 2, p q = 1

p^{3} + q^{3} + 6 p^{2} + 5 q^{2} + 6 p q

p

q

$(q + p) \times (q - p) = ?$

Join BYJU'S Learning Program