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Inverse of a Matrix

Expand :a+b-c...

Question

Expand :
$(a + b - c)^{2}$

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Solution

Step 1: Take $(a + b)$ as single term and expand.
$(a + b - c)^{2} = (a + b)^{2} - 2 \times (a + b) \times c + (c)^{2}$
$= (a + b)^{2} - 2 a c - 2 b c + c^{2}$

Step 2: Now apply the formula of square of sum of two terms.
$(a + b - c)^{2} = a^{2} + b^{2} + 2 a b - 2 a c - 2 b c + c^{2}$
$[∵ (a + b)^{2} = a^{2} + 2 \times a \times b + b^{2}]$
Hence, $(a + b - c)^{2} = a^{2} + b^{2} + c^{2} + 2 a b - 2 a c - 2 b c$

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(a + b + c)^{2}

{(- a + b - c)}^{2}

Q. Expand the following formulas

\begin{matrix} (a + b)^{2} = a^{2} - b^{2} = (a + b + c)^{2 =} \end{matrix}

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Inverse of a Matrix

Standard XII Mathematics

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