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Byju's Answer
Standard XII
Mathematics
Minor
Expand 3 ...
Question
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∣
∣ ∣
∣
3
2
5
9
−
1
4
2
3
−
5
∣
∣ ∣
∣
by sarrus rule.
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Solution
Here,
Δ
=
∣
∣ ∣
∣
3
2
5
9
−
1
4
2
3
−
5
∣
∣ ∣
∣
∴
Δ
=
P
−
N
=
166
−
(
−
64
)
=
230
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