Expand ${(\frac{7}{9})}^{3}$ .

$\frac{343}{729}$

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$\frac{729}{343}$

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$\frac{49}{81}$

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$\frac{81}{49}$

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Solution

The correct option is A
$\frac{343}{729}$

${(\frac{7}{9})}^{3} = \frac{7 \times 7 \times 7}{9 \times 9 \times 7} \Rightarrow {(\frac{7}{9})}^{3} = \frac{343}{729}$

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