According to question, (2a+12a)^3 #160; (2a)^3+(12a)^3+3.(2a)^2.12a+3.2a.(12a)^2 #160; 8a^3+18a^3+6a+32a ...

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Algebraic Identities

Expand: 2a+...

Question

Expand:
${(2 a + \frac{1}{2 a})}^{3}$

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Solution

According to question,

$(2 a + \frac{1}{2 a})^{3}$

$⟹ (2 a)^{3} + (\frac{1}{2 a})^{3} + 3. (2 a)^{2} . \frac{1}{2 a} + 3.2 a . (\frac{1}{2 a})^{2}$

$⟹ 8 a^{3} + \frac{1}{8 a^{3}} + 6 a + \frac{3}{2 a}$

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Similar questions

cos ^2 A (3 - 4 cos ^2 A)^2 + sin ^2 A( 3 - 4 sin ^2 A) ^2 equal to

Expand :

(i) $(2 a + b)^{3}$

(ii) $(a - 2 b)^{3}$

(iii) $(3 x - 2 y)^{3}$

(iv) $(x + 5 y)^{3}$

(v) ${(a + \frac{1}{a})}^{3}$

(vi) ${(2 a - \frac{1}{2 a})}^{3}$

cos θ = \frac{1}{2} (a + \frac{1}{a})

cos 3 θ = \frac{1}{2} (a^{3} + \frac{1}{a^{3}})

(2 a - \frac{1}{2 a})^{3}

8 a^{3} - 6 a + \frac{3}{2 a} - \frac{1}{8 a^{3}}

(ρ)

(a)

(T)

k

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