Step 1: Applying the formula of the square of the difference of two terms: (2x 12x)^2 = (2x)^2 2 × (2x) ×1(2x) + ( 12x)^2 [∵ (a b)^2 = a^2 + b^2 2ab) = 4 ...

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Standard XIII

Mathematics

Middle Terms

Expand 2x - 1...

Question

Expand ${(2 x - \frac{1}{2 x})}^{2}$

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Solution

Step 1: Applying the formula of the square of the difference of two terms:
${(2 x - \frac{1}{2 x})}^{2} = (2 x)^{2} - 2 \times (2 x) \times \frac{1}{(2 x)} + {(\frac{1}{2 x})}^{2}$
$[∵ (a - b)^{2} = a^{2} + b^{2} - 2 a b)$
$= 4 x^{2} - 2 + \frac{1}{4 x^{2}}$
Hence,
${(2 x - \frac{1}{2 x})}^{2} = 4 x^{2} - 2 + \frac{1}{4 x^{2}}$

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Middle Terms

Standard XIII Mathematics

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Expand (2x−12x)2

Step 1: Applying the formula of the square of the difference of two terms: (2x−12x)2=(2x)2−2×(2x)×1(2x)+(12x)2 [∵(a−b)2=a2+b2−2ab) =4x2−2+14x2 Hence, (2x−12x)2=4x2−2+14x2

Expand ${(2 x - \frac{1}{2 x})}^{2}$