log _ 10 385 =log _ 10 55× 7 =log _ 10 55 +log _ 10 7 =log _ 10 5 +log _ 10 7 +log _ 10 11 ...

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Expand log1...

Question

Expand ${log}_{10} 385$ .

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Solution

We have, ${log}_{10} 385$
$= {log}_{10} 55 \times 7$
$= {log}_{10} 55 + {log}_{10} 7$ [ ${log}_{a} (b \times c) = {log}_{a} b + {log}_{a} c$ ]
$= {log}_{10} (11 \times 5) + {log}_{10} 7$
$= {log}_{10} 11 + {log}_{10} 5 + {log}_{10} 7$

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{log}_{10} 385

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Water is cooled from $4^{\circ} C t o 0^{\circ} C$ . It :

(a) contracts (b) expands

(d) first expands, then contracts.

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