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Byju's Answer
Standard VIII
Mathematics
Multiplication of Any Polynomial
Expand: n - ...
Question
Expand:
(
n
−
1
)
(
n
+
1
)
(
n
2
+
1
)
Open in App
Solution
As we know the formula
(
a
+
b
)
(
a
−
b
)
=
a
2
+
b
2
So
(
n
−
1
)
(
n
+
1
)
=
n
2
−
1
2
Substituing the value of
(
n
−
1
)
(
n
+
1
)
=
n
2
−
1
2
in
(
n
−
1
)
(
n
+
1
)
(
n
2
+
1
)
we get:
(
n
−
1
)
(
n
+
1
)
(
n
2
+
1
)
=
(
n
2
−
1
)
(
n
2
+
1
)
=
(
n
2
)
2
−
(
1
)
2
Using: [
(
a
+
b
)
(
a
−
b
)
=
a
2
+
b
2
]
Hence,
(
n
−
1
)
(
n
+
1
)
(
n
2
+
1
)
=
(
n
4
−
1
)
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0
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