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Question

Expand:(n1)(n+1)(n2+1)

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Solution

As we know the formula (a+b)(ab)= a2+b2
So (n1)(n+1) = n212
Substituing the value of (n1)(n+1) = n212 in (n1)(n+1)(n2+1) we get:
(n1)(n+1)(n2+1)=(n21)(n2+1)
=(n2)2(1)2 Using: [(a+b)(ab)= a2+b2]
Hence, (n1)(n+1)(n2+1)=(n41)

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