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Question

Expand the algebraic expression a13(a32+a3)

A
a116+a103
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B
a116+a73
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C
a76+a103
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D
a56+a103
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Solution

The correct option is A a116+a103
a13(a32+a3)=a13a32+a13a3
Using Distributive property of multiplication
=a13+32+a13+(3)
Applying laws of exponents
=a26+96+a13+93
=a116+a103 (a0)

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