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Question

Expand the expression (2x3)6

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Solution

Using Binomial theorem,
(2x3)6=6C0(2x)66C1(2x)5(3)+6C2(2x)4(3)26C3(2x)3(3)3+6C4(2x)2(3)46C5(2x)(3)5+6C6(3)6
=64x66(32x5)(3)+15(16x4)(9)20(8x3)(27)+15(4x2)(81)6(2x)(243)+729
=64x6576x5+2160x44320x3+4860x22916x+729

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