Question

Expand the expression using BODMAS rule: $x^2-x\left[\right(-x\left)\right(-2+x\left)\right]÷x+x^3-3x^2$

• A. $x^3-x^2-2x$
• B. $-x^3-x^2-2x$
• C. $x^3-x^2+2x$
• D. $x^3+x^2+2x$

Answer 1

Answer: (A)

$x^3-x^2-2x$

$x^2-x\left[\right(-x\left)\right(-2+x\left)\right]÷x+x^3-3x^2$
We need to follow BODMAS rule.
=> Brackets (parts of a calculation inside brackets always come first).
=> Orders (numbers involving powers or square roots).
=> Division.
=> Multiplication.
=> Addition.
=> Subtraction.
$=$ $-2x^2-x\left[\frac{(-x)(-2+x)}{x}\right]+x^3$
$=$ $-2x^2-x[2-x]+x^3$
$=$ $x^3-2x^2-2x+x^2$
$=$ $x^3-x^2-2x$