Expand the following binomial:
${(x - 3)}^{5}$

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Solution

On expanding according to binomial theorem we get
${(x - 3)}^{5}$
$= x^{5} +^{5} C_{1} (- 3) x^{4} +^{5} C_{2} (- 3)^{2} x^{3} +^{5} C_{3} (- 3)^{3} x^{2} +^{5} C_{4} (- 3)^{4} x +^{5} C_{5} (- 3)^{5}$
$= x^{5} - 15 x^{4} + 90 x^{3} - 270 x^{2} + 405 x - 243$

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