Expand the following indentity (2x+1)³ ?
(2x+1)3
Using identity (x+y)3 = x3 + y3 + 3xy(x + y)
= (2x)3 + (1)3 + 3(2x)(1)(2x + 1)
= 8 x3+ 1 + 6x(2x + 1)
= 8x3 + 1 + 12x2 + 6x
Expand the following identity. (2x+1)3
Write the following cubes in expanded form: (2x+1)3
Write the following cubes in expanded form:
(i) (2x+1)3
(ii)(2a−3b)3
(iii) (32x+1)3
(iv) (x−23y)3