Expand the following using identities (3x-4y)2.
Given (3x–4y)2
Using Identity (a-b)2=a2–2ab+b2
(3x–4y)2=(3x)2–2.(3x).(4y)+(4y)2
We get,
(3x–4y)2=9x2–24xy+16y2.
Question 85 (vi)
Expand the following, using suitable identities.
(x+3)(x+7)