Question

Expand the following using identity ${(\frac{3p}{2}-\frac{q}{3})}^2$

Answer 1

Given: ${(\frac{3p}{2}-\frac{q}{3})}^2,$

using the identity ${(a-b)}^2=a^2+b^2-2ba$

putting $a=\frac{3p}{2}$ and $b=\frac{q}{3}$,

${\left(\frac{3p}{2}\right)}^2+{\left(\frac{q}{3}\right)}^2-2\left(\frac{3p}{2}\right)\left(\frac{q}{3}\right)=\frac{9p^2}{4}+\frac{q^2}{9}-pq$ (Answer)