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Question

Expand the following, using suitable identities: (3a-7b-c)2


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Solution

Given (3a-7b-c)2

Using identity

(x+y+z)2=x2+y2+z2+2xy+2yz+2z

Here,x=3a,y=7b,z=c

Therefore, (3a7bc)2=(3a)2+(-7b)2+(-c)2+(2×3a×-7b)+(2×-7b×-c)+(2×c×3a)

Hence, (3a7bc)2=9a2+49b2+c242ab+14bc6ca


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