wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

Expand the following, using suitable identities: (14a12b+1)2 [3 MARKS]

Open in App
Solution

Formula: 1 Mark
Substitution: 1 Mark
Calculation: 1 Mark

(14a12b+1)2
Using the identity

(a+b+c)2=a2+b2+c2+2(ab+bc+ca) ....(1)

a=14a,b=12b,c=1
Substituting the values of a,b,c in identity(1)

=(14a)2+(12b)2+(1)2+2(14a)(12b)+2(12b)(1)+2(1)(14a)

=116a2+14b2+114abb+12a


flag
Suggest Corrections
thumbs-up
273
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualisation of (x+a)(x+b)
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon