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Question

Expand the following, using suitable identity.
(xy+yz+zx)2

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Solution

We have, (xy+yz+zx)2
(a+b+c)2=a2+b2+c2+2ab+2bc+2ca
=(xy)2+(yz)2+(zx)2+2.xy.yz+2.yz.zx+2.zx.xy
=x2y2+y2z2+z2x2+2xz+2yx+2zy

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