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Question

Expand this: (3x+4y)(3x+5y).


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Solution

Given: (3x+4y)(3x+5y)

(3x+4y)(3x+5y)=3x(3x+5y)+4y(3x+5y)

=9x2+15xy+12xy+20y2

=9x2+27xy+20y2

Hence(3x+4y)(3x+5y)=9x2+27xy+20y2


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