Expand using identities: $(2 x y + 5 y)^{2}$

y^{2} (4 x^{2} - 89 x + 25)

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y^{2} (4 x^{2} + 56 x + 13)

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y^{2} (4 x^{2} + 20 x + 25)

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y^{2} (x^{2} + 20 x + 5)

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Solution

The correct option is C $y^{2} (4 x^{2} + 20 x + 25)$
$(2 x y + 5 y)^{2}$
Using, $(a + b)^{2} = a^{2} + b^{2} + 2 a b$
$= (2 x y)^{2} + (5 y)^{2} + 2 (2 x y) (5 y)$
$= 4 x^{2} y^{2} + 25 y^{2} + 20 x y^{2}$
$= y^{2} (4 x^{2} + 25 + 20 x)$

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Similar questions

y^{2} (4 x^{2} - 108) = x (x^{3} - 9 y^{3}), 2 x^{2} + 9 x y + y^{2} = 108

4 x^{2}

{4 x}^{2} + 20 x + 25

Factorize:

$(x + 2) (x^{2} + 25) - 10 x^{2} - 20 x$

4 x^{2} + 20 x + 25

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