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Question

Expand using identity : (3x−5y−2z)(3x−5y+2z)

A
9x230xy+20y24z2
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B
9x230xy+15y24z2
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C
9x230xy+12y24z2
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D
9x230xy+25y24z2
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Solution

The correct option is D 9x230xy+25y24z2
(3x5y2z)(3x5y+2z)
=(3x5y)2(2z)2
Using,
(ab)2=a22ab+b2)
=[(3x)22(3x)(5y)+(5y)2](2z)2
=9x230xy+25y24z2

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