wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Expand (x+1)3 using an identity

Open in App
Solution

(x+1)3
We know that (x+y)3=x3+y3+3xy(x+y)
Here x=x and y=1 we get
(x+1)3=x3+(1)3+3(x)(1)(x+1)
=x3+1+3x(x+1)
=x3+1+3x2+3x
=x3+3x2+3x+1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
(x+a)(x+b)
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon