Expand $(x - 3) (x - 1) + (y - 2) (y - 4)$

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Solution

Consider the given,

$\Rightarrow (x - 3) (x - 1) + (y - 2) (y - 4)$

$\Rightarrow x^{2} - 4 x + 3 + y^{2} - 6 y + 8$

$\Rightarrow x^{2} + y^{2} - 4 x - 6 y + 11$

Hence, this is the answer.

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Similar questions

(3 x - 2 y + 4) (3 x - 2 y - 4)

3 x + 2 y - 4

x = 2

y = (- 1)

\frac{3 x + y}{x - 1} - \frac{x - y}{2 y} = 2, x - y = 4

3 x - y + 2 z - 1 = 0 = x + 2 y - z - 2

3 x + 2 y + z = 0

{(3 x + 2 y)}^{4}

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