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Empirical & Molecular Formula

Experimental ...

Question

Experimental analysis shows that a compound contains $0.015$ moles of iron and $0.0225$ moles of sulfur. What is the empirical formula of this compound?

A

{F e}_{2} S_{3}

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B

{F e}_{3} S

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C

F e S

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D

{F e}_{7} S_{8}

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Solution

The correct option is A ${F e}_{2} S_{3}$
Empirical formula is the simplest whole number ratio of elements present in the compound.
The ratio of iron to sulphur is $0.015 : 0.0225 = 10 : 15 = 2 : 3$
So, the empirical formula is $F e_{2} S_{3}$

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