Explain about chain rule?
If $y + l o g_{a} x + l o g_{x} a + l o g_{a} a$ then $\frac{d y}{d x} =$

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Solution

$y = l o g_{a} x + l o g_{x} a + l o g_{x} x + l o g_{a} a$
$= \frac{l o g x}{l o g a} + \frac{l o g a}{l o g x} + 1 + \frac{l o g a}{l o g a}$
$\frac{d y}{d x} = \frac{1}{l o g a} \frac{1}{x} + l o g a (\frac{- 1}{(l o g x)^{2}}) \frac{1}{x} + 0 + 0$
$= \frac{1}{x l o g a} - \frac{l o g a}{x (l o g x)^{2}}$ .

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