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Explain about ionization enthalpy ? Why IE2>IE1?

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Q. The ionization enthalpies,

(I E)_{1}

(I E)_{2}

^{- 1}

of a few elements designated by Roman numerals are shown below :

Element	$(I E)_{1}$	$(I E)_{2}$
A	2372	5251
B	520	7300
C	900	1760
D	1680	3380

Which of the above elements form a stable binary halide of the formula

M X_{2}

Δ

H (Ionization enthalpy) for the process is 19800 kJ/mole &

I E_{1}

for Li is 520, then

I E_{2}

I E_{3}

L i^{+}

are _______ respectively.

[Note : approx. value]

{I E}_{1}

O < {I E}_{1}

N

{I E}_{2}

O > {I E}_{2}

N

{(I E)}_{1}

{(I E)}_{2}

{m o l}^{- 1}

of K and Ca have been given as

	${(I E)}_{1}$	${(I E)}_{2}$
K	419	3052
Ca	590	1145

The difference can be explained by:

Q. Which represents alkali metals based on

(I E_{1})

(I E_{2})

		$(I E)_{1}$	$(I E)_{2}$
(a)	X	100	110
(b)	Y	95	120
(c)	Z	195	500
(d)	M	200	250

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