Question

Explain graphical method to determine activation energy of a reaction.

Answer 1

Arrhenius equation is $\ln k=\ln A-\frac{Ea}{RT}$
Taking $\log 10$ , ${\log }_{10}k=-\frac{Ea}{RT}+{\log }_{10}A$
${\log }_{10}k$ is plotted against $1/T$, the graph is straight line.
In graph slope $=A-\frac{Ea}{2.303R}$
$\therefore Ea=-slope\times 2.303\times R$