Question

Explain, how is the electronegativity of carbon atoms related to their state of hybridisation in an organic compound?

Answer 1

Electronegativity of carbon atoms increases as the percentage of the s-character in their state of hybridisation increases. This is because s-electrons are more strongly attracted to the nucleus than p-electrons.

Hybridisation	Percentage of s-character	Percentage of p-character
$sp$	50	50
$s{p}^2$	33	67
$s{p}^3$	25	75

Therefore, order of electronegativity will be: $s{p}^3<s{p}^2<sp.$