Question

Explain hybridization of central atom in $N{O}_3^{-}$

Answer 1

Hybridisation $=\frac{1}{2}$ (Valence electrons $+$ No. of Monovalent atoms $-$ Cationic charge $+$ Anionic charge)

For compound ${NO}_3^{-}$

$=\frac{1}{2}(5+0-0+1)=\frac{6}{2}=3={SP}^2$

Ans :- ${sp}^2$ hybridisation.