explain oxidation numbdr method by acidic medium

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C r_{2} O_{7 (a q)}^{2 -} + I_{(a q)}^{-} \to C r_{(a q)}^{3 +} + I O_{3 (a q)}^{-}

How to balance this by oxidation number method $H_{2} O_{2} (a q) + F e^{2} (a q) + ⟶ F e^{3} (a q) + H_{2} O (l)$ [in acidic medium)

H_{2} O_{2} + C r_{2} O_{7 (a q)}^{2 -} \to O_{2 (g)} + C r_{(a q)}^{3 +}

H_{2} O_{2 (a q)} + C r_{2} O_{7}^{2 -} (a q) \to O_{2 (g)} + C r_{(a q)}^{3 +}

S_{4} O_{6}^{2 -} (a q) + A l (s) \to H_{2} S (a q) + A l^{3 +} (a q)

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