Explain Potential energy stored in stretched wire with diagram

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Solution

Dear Student,

The Potential Energy of a stretched wire is given by,

PE = ½ × stress × strain × volume

=> PE = ½ × (F/A) × (ΔL/L) × (AL)

Now,

Y = (F/A)/(ΔL/L)

=> F = AYΔL/L

So, PE = ½ × (YΔL/L) × (ΔL/L) × (AL)

=> PE = AY(ΔL)²/(2L)

Regards.........

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Explain Potential energy stored in stretched wire with diagram

Dear Student, The Potential Energy of a stretched wire is given by, PE = ½ × stress × strain × volume => PE = ½ × (F/A) × (ΔL/L) × (AL) Now, Y = (F/A)/(ΔL/L) => F = AYΔL/L So, PE = ½ × (YΔL/L) × (ΔL/L) × (AL) => PE = AY(ΔL)2/(2L) Regards.........

Dear Student,

The Potential Energy of a stretched wire is given by,

PE = ½ × stress × strain × volume

=> PE = ½ × (F/A) × (ΔL/L) × (AL)

Now,

Y = (F/A)/(ΔL/L)

=> F = AYΔL/L

So, PE = ½ × (YΔL/L) × (ΔL/L) × (AL)

=> PE = AY(ΔL)²/(2L)

Regards.........