Explain reason:
a) Grignard reagent should be prepared under anhydrous conditions.
b) $C_{6} H_{5} C H C l C H_{3}$ is hydrolysed more easily with KOH than $C_{6} H_{5} C H_{2} C l$

Open in App

Solution

Grignard reagents are very reactive. In the presence of moisture, they react to give alkanes. Therefore, Grignard reagents should be prepared under anhydrous conditions.
$R M g X + H - O H D r y e t h e r - ----- \to R - H + M g (O H) X$
When $H_{2} O$ attacks the $2^{0}$ alkyl halide $C_{6} H_{5} - C H C l - C H_{3}$ , the carbocation thus formed has resonance and hyperconjugation to stabilize it.
In $C_{6} H_{6} C H_{2} C l$ , only resonance is present.
Hence, the difference

Suggest Corrections

Similar questions

M e M g B r

Explain why

The dipole moment of chlorobezene is lower than that of cyclohexyl chloride ?

alkyl halides, though polar, are immiscible with water ?

Grignard reagents should be prepared under anhydrous conditions ?

Out of C₆H₅CH₂Cl and C₆H₅CHClC₆H₅, which is more easily hydrolysed by aqueous KOH?

Explain why

(i) the dipole moment of chlorobenzene is lower than that of cyclohexyl chloride?

(ii) alkyl halides, though polar, are immiscible with water?

(iii) Grignard reagents should be prepared under anhydrous conditions?

Join BYJU'S Learning Program