Explain the bonding on $C o C l_{2} .3 N H_{3}$ and $C o C l_{2} .5 N H_{3}$ structure on the basis at Werner's theory.

Open in App

Solution

$C o C l_{3} .5 N H_{3}$ complex
_____________________
Co-ordination number of $C o$ is $6$ . One remaining position is occupied by $C l^{-}$ ion. $C l^{-}$ ion exhibits the dual behaviour as it has a primary as well as secondary valency.
(Refer to Image)
Number of $C l^{-}$ ions precipitated= $2$
Total number of ions= $3$
Formula= $[C o C l (N H_{3})_{5}] C l_{2}$

$C o C l_{3} .3 N H_{3}$ complex
_____________________
$3 C l^{-}$ ions satisfy primary as well as secondary valency. No $C l^{-}$ ion will be precipitated on the addition of $A g N O_{3}$ at room temperature.
$∴$ Complex behave as neutral non-conducting molecule.
(Refer to Image 2)

Suggest Corrections

Similar questions

[F e (C N)_{6}]^{- 4}

F e = 26

[N i (C O)_{4}]

Explain on the basis of valence bond theory that [Ni(CN)₄]²⁻ ion with square

planar structure is diamagnetic and the [NiCl₄]²⁻ ion with tetrahedral geometry is paramagnetic.

C o C l_{3} {4 N H}_{3}

A g {N O}_{3}

{C l}^{-}

{C l}^{-}

Join BYJU'S Learning Program