Explain the change in the hybridization of $(S i H_{3})_{2} O$ .

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Solution

The hybridization of ${(S i H_{3})}_{2} O$ has been changed from ${s p}^{3}$ to ${s p}^{2}$ .

$S i$ has vacant $d$ orbital which can take part in back bonding, i.e, $P_{Π} \to d_{Π}$ back bonding by accepting back the lone pair of electrons of $O$ atoms to its vacant $d$ orbital.

As a result, it hybridization changes from ${s p}^{3}$ to ${s p}^{2}$ .

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