Explain the concept of single electrode potential by taking a solution of iron rod dipped in $F e S O_{4}$ solution and a solution of $C u$ rod dipped in $C u S O_{4}$ solution separately. Can we measure the potential in the above cases when they are taken separately ? Give reason.

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Solution

When iron rod is dipped in ${F e S O}_{4}$ solution, $F e$ atoms lose electron and a larger of negative charge surround the $C u$ rod and the potential developed at the interface of $C u$ rod and $C u S O_{4}$ is called reduction potential of $C u$ . It is not possible to measure the potentials in the above cases when they are taken separately. This is because when the metal rod is connected to voltmeter by a metallic wire for measuring the potential, the metallic wire changes the potential of metal rod.

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