Question

Explain the expression in second closed organ pipe.
$l=3\frac{\lambda }{4}\lambda =\frac{4L}{3}\begin{array}{c}{n}_8=\frac{3v}{4L}\\ \lambda =3v_0\end{array}\}$

Answer 1

For closed organ pipe,
$l=(2n+1)\frac{\lambda }{4}$
$\therefore Frequency,v=\frac{v}{\lambda }$ $=(2n+1)\frac{v}{\lambda }$
$Whenn=0,r_0=\frac{v}{4l}$
$Whenn=1,v=\frac{3v}{4l}=3v_0$