MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Covalent Bonding in Similar Atoms

Explain the f...

Question

Explain the formation of a double bond in oxygen molecule.

Open in App

Solution

In oxygen molecule, the double bond contains one sigma and one pi bond.
Oxygen atom has six valence electrons. Oxygen molecule has two oxygen atoms. Each O atom shares 2 electrons to form two covalent bonds out of which one is sigma bond and other is pi bond. Sigma bond is formed by axial overlap 2p atomic orbitals of oxygen and pi bond is formed of lateral overlap of 2p atomic orbitals of oxygen. In oxygen molecule, both oxygen atoms have completed their octet.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Draw diagrams showing the formation of a double bond and a triple bond between carbon atoms in

C_{2} H_{4}

C_{2} H_{2}

Q. The formation of a double bond in an oxygen molecule is explained below. Arrange the given points in a sequential order.
(a) 2p

_{y}

orbitals of each oxygen atom overlap laterally/sidewise to form a pi bond.
(b) Thus, a double bond between two oxygen atoms in which one p

_{z}

_{z}

sigma bond and p

_{y}

_{y}

π

bond is formed.
(c) All the three 2p orbitals are perpendicular to each other. Hence 2p

_{z}

orbitals of each oxygen atom overlap end to end to form a sigma bond.
(d) The electronic configuration of oxygen is

O

^{2}

^{2}

_{x}^{1}

_{y}^{2}

_{z}^{1}

Q. How many Pi electrons are there in the Double covalent bond of oxygen molecule

Q. Explain the formation of the following molecules using valence bond theory
(a)

N_{2}

O_{2}

Q. Explain the formation of

H_{2}

molecule on the basis of valence bond theory.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Covalent Bonding in Similar Atoms

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Covalent Bonding in Similar Atoms

Standard VIII Chemistry

Join BYJU'S Learning Program

CrossIcon