Question

Explain the formation of following compound:

$CaO$
$Ca:\left[Ar\right]4s^2⟶C{a}^{2+}\left[Ar\right]O:1s^{2}2s^{2}2p^4⟶O^{2-}1s^{2}2s^{2}2p^{6}C{a}^{2+}[:\underset{\cdot \cdot }{\ddot{O}}:{]}^{2-}$
If true enter 1, else enter 0.

Answer 1

$Ca$ loses to electrons to form $C{a}^{2+}$ which is gained by $O$ to form $O^{2-}$ resulting in the formation of $CaO$.
$Ca:\left[Ar\right]4s^2⟶C{a}^{2+}\left[Ar\right]$
$O:1s^{2}2s^{2}2p^4⟶O^{2-}1s^{2}2s^{2}2p^6$
$C{a}^{2+}+O^{-2}\to CaO$