Explain the hydrides of nitrogen family under the following points: (i) Name and formula, (ii) Basic property, (iii) Reducing property, (iv) Bond angle, (v) Melting and Boiling point
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Solution
(i) Name and formula Name Formula (1) Nitrogen: Ammonia Nitric Acid NH3 HNO3 (2) Phosphorous: Phosphine PH3 (ii) Basic property: Ammonium is a mono basic anhydride that dissolves in water in in form of NH4OH (ammonium) hydroxide. Ammonium hydroxide is a base. Hence, it has a more basic nature. Nitric acid is also a strong mono-basic acid which ionized in water and form of H3O+ and NNO−3 ions. Hence, it has also more basic nature. Phosphene combine with halogen acids in gaseous state and forms phosphonium. There phosphonium halides decompoe as soon as possible and reform phospone. PH3+HX→PH4XPhosphonium halide [X = Cl, Br or I] PH4XH2O−−→PH3−H+X Hence it has more acidic property due to formation of H+ and it has also more basic nature. Therefore, it is clear that hydrides of Nitrogen and Nitrogen family has more basic nature. (ii) Reducing property: Ammonia gas is a strong reducing agent. It reduces hot metallic oxides into metals. Nitric acid is a strong oxidant i.e. reducing agent, as it easily decomposes to produce nascent oxyen. 2HNO3→H2O+2NO2+[O]Nitrogen di-oxide On passing phosphene gas into the solutions of copper silver and mercury salts metal phosphides are precipitated. 3CuSO4+2PH3→Cu3P2+3H2SO4 3HgNO3+PH3→Ag3P+3HNO3 Hence, it has strong reducing property. Therefore, from the above reasons and explanation it is clear that hydrogen of nitrogen family have strong reducing property. (iv) Bond angle Ammonia: (ref. image) Bond angle is 107.3o. (v) Melting and boiling points: Melting point (except for Sb and Bi) and boiling point increase on going down the group from N to B. This is because, electropositive and metallic character increase and hence binding energy of atomic crystal also increases.