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Question

Explain the hydrides of nitrogen family under the following points:
(i) Name and formula, (ii) Basic property,
(iii) Reducing property, (iv) Bond angle,
(v) Melting and Boiling point

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Solution

(i) Name and formula Name Formula
(1) Nitrogen: Ammonia Nitric Acid NH3
HNO3
(2) Phosphorous: Phosphine PH3
(ii) Basic property: Ammonium is a mono basic anhydride that dissolves in water in in form of NH4OH (ammonium) hydroxide.
Ammonium hydroxide is a base. Hence, it has a more basic nature. Nitric acid is also a strong mono-basic acid which ionized in water and form of H3O+ and NNO3 ions.
Hence, it has also more basic nature. Phosphene combine with halogen acids in gaseous state and forms phosphonium. There phosphonium halides decompoe as soon as possible and reform phospone.
PH3+HXPH4XPhosphonium halide [X = Cl, Br or I]
PH4XH2OPH3H+X
Hence it has more acidic property due to formation of H+ and it has also more basic nature.
Therefore, it is clear that hydrides of Nitrogen and Nitrogen family has more basic nature.
(ii) Reducing property: Ammonia gas is a strong reducing agent. It reduces hot metallic oxides into metals.
Nitric acid is a strong oxidant i.e. reducing agent, as it easily decomposes to produce nascent oxyen.
2HNO3H2O+2NO2+[O]Nitrogen di-oxide
On passing phosphene gas into the solutions of copper silver and mercury salts metal phosphides are precipitated.
3CuSO4+2PH3Cu3P2+3H2SO4
3HgNO3+PH3Ag3P+3HNO3
Hence, it has strong reducing property.
Therefore, from the above reasons and explanation it is clear that hydrogen of nitrogen family have strong reducing property.
(iv) Bond angle Ammonia: (ref. image)
Bond angle is 107.3o.
(v) Melting and boiling points: Melting point (except for Sb and Bi) and boiling point increase on going down the group from N to B. This is because, electropositive and metallic character increase and hence binding energy of atomic crystal also increases.
666739_628371_ans_d5b2c74930b74706853da68fae5aff56.png

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