Question

Explain why '$F$' is strongest oxidising agent.

Answer 1

Electronic configuration of $F=1s^2,2s^2,2p^5$.

Thus, $F$ needs only one more electron to complete its octet and to attain the stable noble gas configuration. Also, $F$ is highly electronegative with low dissociation energies and high negative electron gain enthalpies. Therefore, fluorine has a high tendency to gain an electron. Hence, it acts as a strong oxidising agent.