wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Explain why (CH3)3C is more stable than CH3CH2 and CH3 is less stable.

A
Hyperconjugation
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Resonance
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Tautomerism
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Inductive effect
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct options are
B Hyperconjugation
C Inductive effect
Hyperconjugation interaction in (CH3)3C (I) is greater than that of C in CH3CH2 (II), as (I) has nine (CH) bonds and (II) has three (CH) bonds.<br><br>In CH3, the vacant p orbital is perpendicular to the plane in which (CH) bond lies; hence cannot overlap with it. <br><br>Thus, CH3 lacks hyperconjugative stability.
Also, as the number of alkyl groups increases, the +I effect increases and the electron density on positively charged carbon increases.
Hence, (CH3)3C is more stable than CH3CH2 and CH3 is less stable.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hybridisation
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon