Explain why $N_{2}$ has greater bond dissociation energy than $N_{2}^{+}$ whereas $O_{2}$ has lesser bond dissociation energy than $O_{2}^{+}$

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Solution

$N_{2}$ has bond order $^{'} 3^{'}$ and $N_{2}^{+}$ , it is $2.5$ . Great bond order has higher bond dissosiation energy. So $N_{2}$ has more bond dissosiation energy than $N_{2}^{+}$ . For $O_{2}$ bond order is $2$ . For $O_{2}^{+}$ , bond order is $2.5$ . So, bond dissociation is greater for $O_{2}^{+}$ .

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