It is coupling between aryl halide and alkyl halide in presence of sodium metal in dry ether to form alkyl benzene.
Ph−Br+CH3Br+2Nadryether−−−−−→Ph−CH3+2NaBr
During this reaction, following side products are obtained.
2Ph−Br+2Nadryether−−−−−→Ph−Ph(Diphenyl)+2NaBr
2CH3−Br+2Nadryether−−−−−→CH3−CH3+2NaBr