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If (x+a) is a factor of 2x2+2ax+5x+10 find a

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#. If (x+a) is a factor of 2x2+2ax+5x+10 find a


Ans:
X+a is a factor of 2x²+2ax+5x+10
therefore f(-a)=0;
substituting values,
2(-a)²+2(a)(-a)+5(-a)+10=0
2a²-2a²-5a+10=0
-5a+10=0
therefore a=2

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